This is a small how to on listing all the users in a box. This is bit tricky but if you give a thought you will realize that user info is in passwd file, so if you can grep the first field then it’s done.

The passwd file content for your reference
gdm:x:113:120:Gnome Display Manager:/var/lib/gdm:/bin/false


mediatomb:x:114:123:MediaTomb Server,,,:/var/lib/mediatomb:/usr/sbin/nologin

haldaemon:x:115:124:Hardware abstraction layer,,,:/var/run/hald:/bin/false

How to get only user values?

Use cut command to cut the fields..

cat /etc/passwd | cut -d: -f1

Let me explain above command

we are opening file /etc/passwd with cat command and then redirecting output to a cut command which will cut the first field(-f1) ie user ID field using : as delineated(-d:). As you know passwd file content are separated with colon(:)

Sample output of the above command

cat /etc/passwd | cut -d: -f1











This is how we can list all the users. If you want to list all the groups in the machine we can use below command

cat /etc/group | cut -d: -f1

Please share your thoughts on this, how you do if you have same situation.

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Mr Surendra Anne is from Vijayawada, Andhra Pradesh, India. He is a Linux/Open source supporter who believes in Hard work, A down to earth person, Likes to share knowledge with others, Loves dogs, Likes photography. He works as Devops Engineer with Taggle systems, an IOT automatic water metering company, Sydney . You can contact him at surendra (@) linuxnix dot com.